\(Q1\)
$$a_1=2, a_{n+1}=a_n^2$$
$$A. a_n=2^{2^{n-1}}$$
You will see a similar problem in EJU Math advanced course 2 2011 1st Section 2
If you would like to know more about Special types of recurrence relations, check the link below
Practice Questions: Sequence Special Type: Log
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